14x^2=40x+6

Solution for 14x^2=40x+6 equation:

14x^2=40x+6

We move all terms to the left:

14x^2-(40x+6)=0

We get rid of parentheses

14x^2-40x-6=0

a = 14; b = -40; c = -6;
Δ = b2-4ac
Δ = -402-4·14·(-6)
Δ = 1936
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1936}=44$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-44}{2*14}=\frac{-4}{28}
=-1/7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+44}{2*14}=\frac{84}{28}
=3
$